Monday, July 10, 2017

1.29: Calculate Reacting Masses Using Experimental Data and Chemical Equations



REACTING MASSES: Chemical equations can be used to calculate the Moles or Masses of Reactants and Products
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  • Use information from the question to find the Mole of a Substance / Reactant
  • Identify the ratio of the substance and reactants and find the Moles of others
  • Apply Mole calculations to find answer


Example 1:
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Calculate the Mass of Magnesium Oxide that can be made by Completely Burning 6 g of Magnesium in Oxygen
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Magnesium (s)  + Oxygen (g)  →   Magnesium Oxide (s)  

SYMBOL EQUATION:     2Mg     +     O2       →       2MgO

RELATIVE FORMULA MASS:    Magnesium : 24             Magnesium Oxide : 40

STEP 1 - Calculate the Mol of Magnesium Used in Reaction

               Moles = Mass ÷ Mr                                       Moles = 6 ÷ 24 = 0.25


STEP 2 - Find the Ratio of Magnesium to Magnesium Oxide using Chemical Equation

                                        Magnesium               Magnesium Oxide

               Mol                            2                                      2

               Ratio                         1                                      1
               Mol                          0.25                                 0.25

               Mol of Magnesium Oxide = 0.25


STEP 3 - Find the Mass of Magnesium Oxide

               Moles of Magnesium Oxide = 0.25

               Mass = Moles x Mr                                       Mass = 0.25 x 40 = 10


                                                             Mass of Magnesium Oxide Produced = 10 g





Example 2:
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Calculate the Mass, in Tonnes, of Aluminium that can be produced from 51 Tonnes of Aluminium Oxide
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Aluminium Oxide (s)  →   Aluminium (s)   +   Oxygen (g)

SYMBOL EQUATION:     Al2O3     →       2Al       +       3O2

RELATIVE FORMULA MASS:  Aluminium : 27    Oxygen : 16    Aluminium Oxide : 102

1 Tonne = 106 g

STEP 1 - Calculate the Mol of Aluminium Oxide Used

              Mass of Aluminium Oxide in Grams = 51 x 106 = 51000000  

              Moles = Mass ÷ Ar                               Moles = 51000000 ÷ 102 = 1000000


STEP 2 - Find the Ratio of Aluminium Oxide to Aluminium using Chemical Equation

                                        Aluminium Oxide         Aluminium

               Mol                            1                                     2

               Ratio                         1                                     2
               Mol                      1000000                         2000000

               Mol Aluminium = 2000000


STEP 3 - Find the Mass of Aluminium

               Moles of Aluminium = 2000000

               Mass = Moles x Mr                          Mass = 2000000 x 27 = 54000000

               Mass in Tonnes = 54000000 ÷ 106 = 54 Tonnes

                                                               Mass of Aluminium Produced = 54 Tonnes

5 comments:

  1. There is a calculation mistake in example 2, am I right?

    ReplyDelete
    Replies
    1. What is that mistake in Example 2?

      Delete
    2. yeah there is a mistake 51000000/102 = 500000
      in example 2 moles =mass/mr (not moles+mass/ar)

      Delete
  2. There's errors in both of them.

    ReplyDelete