ELECTROLYSIS: Decomposition of an ionic substance by passing an electric current through it
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REACTION AT ELECTRODES:
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SOLUTION
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PRODUCT AT POSITIVE ELECTRODE
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PRODUCT AT NEGATIVE ELECTRODE
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LEAD (II) BROMIDE ( PbBr2 )
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Bromine - Br2
2Br - - 2e- → Br2
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Lead - Pb
Pb2+ + 2e- → Pb
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SODIUM CHLORIDE ( NaCl )
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Chlorine - Cl
2Cl- - 2e- → Cl2
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Hydrogen - H2
2H2O + 2e- → H2 + 2OH-
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DILUTE SULFURIC ACID ( H2SO4 )
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Oxygen - O2
2H2O - 4e- → O2 + 4H+
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Hydrogen - H2
2H+ + 2e- → H2
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COPPER (II) SULFATE ( CuSO4 )
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Oxygen - O2
2H2O - 4e- → O2 + 4H+
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Copper - Cu
Cu2+ + 2e- → Cu
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LEAD (II) BROMIDE ( PbBr2 ) the PRODUCT AT NEGATIVE ELECTRODE can't be Lead because it in a solution and Hydrogen is less reactive then Lead. So the product is Hydrogen.
ReplyDeleteLead (II) Bromide in this case is molten, check the previous syllabus statement. It's the only one of the few not in an aqueous solution. If it was you'd be correct, though.
Deleteyeah thats right
Delete