Sunday, July 9, 2017

3.7C: Use Bond Energies to Calculate the Enthalpy Change during a Chemical Reaction



BOND ENERGY: Energy required to break a bond
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METHOD:
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  • Add all bond energies for all the bonds in reactant - this is the ‘energy in’
  • Add all bond energies for all the bonds in products - this is the ‘energy out’
  • Calculate the energy change: energy in - energy out
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EQUATION:


Energy Change     =     Energy In     -     Energy Out

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Example: An Exothermic Reaction


Hydrogen and Chlorine reacts to form Hydrogen Chloride Gas:



H - H   +   Cl - Cl    →    2    x    (H - Cl)
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Table below shows the bond energies relevant to this reaction:


BOND
BOND ENERGY ( KJ / MOLE )
    H - H
    436
    Cl - Cl
    243
    H - Cl
    432

Energy In    =     436     +     243    =    679 KJ / Mole

Energy Out     =    2    x    243    =    864 KJ / Mole

Energy Change    =    679    -    864    =    -185 KJ / Mole

*Energy change is negative, therefore showing that more energy is given out to the surroundings than taken in, indicating that this is an Exothermic Reaction

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Example: An Endothermic Reaction


Hydrogen Bromide Decomposes to Form Hydrogen and Bromine:



2   x   ( H - Br )    →    H - H    +    Br - Br
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Table below shows the bond energies relevant to this reaction:


BOND
BOND ENERGY ( KJ / MOLE )
    H - Br
    366
    H - H
    436
    Br - Br
    193


Energy In    =     2     x     366    =    732 KJ / Mole

Energy Out     =    436    +    193    =    629 KJ / Mole

Energy Change    =    732    -    629    =    +103 KJ / Mole

*Energy change is positive, therefore showing that more energy is taken in from the surroundings than is given out, indicating that this is an Endothermic Reaction

1 comment:

  1. The calculation for the first one is wrong
    Energy Out = 2 * 432 = 864 KJ/mol
    Thanks

    ReplyDelete